Question

Q.11 - What is the least number of squares tiles required to pave the
floor of a room 30 m 34 cm long and 18 m 4 cm broad?​

Answer 1

Answer :

• 814 tiles is the least number of squares tiles required to pave the floor.

Given :

• Length of the floor of room = 30 m 34 cm.

• Breadth of the floor of room = 18 m 4 cm.

To find :

• The least number of squares tiles required to pave the floor =?

Step-by-step explanation :

Length of the room

= 30 m 34 cm

= 30 × 100 + 34

= 3034 cm.

Breadth of the room

= 18 m 4 cm

= 18 × 100 + 4

= 1804 cm.

The HCF of the 3034 and 1804 will be size of square tiles.

HCF of 3034 and 1804 = 82 cm.

Area of the room

= length × breadth

= 3034 × 1804 cm²

Area of tiles = 82 × 82 cm²

So, number of tiles required

= 3034 × 1804 / 82 × 82

= 814 tiles

Thus, 814 tiles is the least number of squares tiles required to pave the floor.