Q.11 - What is the least number of squares tiles required to pave thefloor of a room 30 m 34 cm long and 18 m 4 cm broad?
PLEASE GIVE STEP BY STEP EXPLANATION
Answers
to find the no. of sq. tiles, we need to find the area
area of room= length×breadth
area of room=30.34×18.4
Answer :
- 814 tiles are required to pave the floor.
Given :
- Length of the floor of room = 30 m 34 cm.
- Breadth of the floor of room = 18 m 4 cm.
To find :
- Number of tiles required to pave the floor =?
Step-by-step explanation :
Length of the floor of room = 30 m 34 cm. [Given]
30 m = 30 × 100 = 3000 cm
∴ Length of the room
= 3000 cm + 34 cm
= 3034 cm.
Breadth of the floor of room = 18 m 4 cm. [Given]
18 m = 18 × 100 = 1800 cm
∴ Breadth of the room
= 1800 cm + 4 cm
= 1804 cm.
The HCF of the 3034 and 1804 will be size of square tiles.
HCF of 3034 and 1804 = 82 cm.
Area of rectangle = Area of the floor = length × breadth
Substituting the values in the above formula, we get,
= 3034 × 1804 cm²
= 5,473,336 cm²
Area of rectangle = Area of tiles = Length × Breadth
= 82 × 82 cm²
= 6,724 cm²
So, number of required tiles = Area of floor / Area of a tile
Substituting the values in the above formula, we get,
= 5,473,336/6,724
= 814
Thus, 814 tiles are required to pave the floor.