Q.11) What is the magnitude of a point charge chosen so that the electric field 50cm away has magnitude 2.0N/C?
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Since,
E=kQ/r^2
=>2=9*10^9*Q/(0.5)^2 [50 cm in meters]
=>2*0.25*10^(-9) / 9 = Q
=>0.055 * 10^(-9) Coulombs = Q
E=kQ/r^2
=>2=9*10^9*Q/(0.5)^2 [50 cm in meters]
=>2*0.25*10^(-9) / 9 = Q
=>0.055 * 10^(-9) Coulombs = Q
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