Q.12. A rocket of mass m is moving with a velocity v. If its velocity becomes three
times, calculate the change in its kinetic energy.
Answers
Answered by
1
Ke=1/2mv2
K'=1/2m(3v)*2
1/2m9v2
So new energy will be 9 t
imes ofealier
K'=1/2m(3v)*2
1/2m9v2
So new energy will be 9 t
imes ofealier
Answered by
1
kinetic energy = 1/ 2 × mv^2
kinetic energy(1) = 1/ 2 × mv^2
kinetic energy (2) = 1/2 m × 3v^2
change = +mv^2 = 200%
kinetic energy(1) = 1/ 2 × mv^2
kinetic energy (2) = 1/2 m × 3v^2
change = +mv^2 = 200%
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