Question

Q. 12 A train starting from rest attains a velocity of 36 km per hour in 50 seconds. Assuming that
the acceleration is uniform, find (a) the acceleration and (b) the distance travelled by the train for
attending this velocity.​

Answer 1

Answer:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km