Question

Q.12. Abody is moving with a speed of 5 m/s. In 5 sec the body comes to rest. Find acceleration
distance covered by the body.​

Answer 1

Explanation:

Initial velocity (u)= 5m/s

final velocity (v) = 0m/s (it comes to rest)

time= 5s

acceleration (a) = v-u/t

= 0-5/5

= -5/5

= -1m/s

so, distance:

• v^2= u^2 -2as
• 0^2 = 5^2 +(2×-1×s)
• 0= 25 - 2s
• 2s=25
• s= 25/2
• s = 12.5m

Therefore, distance = 12.5m

PLEASE MARK AS BRAINLIEST

HOPE THIS HELPS