Question

Q.12 Diagonals AD and BC of a square ABCD. intersect each other at a point
0. If OA = 7 cm, then AD and BC are respectively. [Mention the property
used]


​

Answer 1

Given :- Diagonals AD and BC of a square ABCD. intersect each other at a point O. If OA = 7 cm, then AD and BC are respectively. ?

Solution :-

we know that,

• The diagonals of a square bisect each other .

so,

→ OA = 7 cm. (given)

and,

→ OA = OD (By above told property .)

then,

→ AD = AO + OD

→ AD = 7 + 7

→ AD = 14 cm. (Ans.)

now, we know that,

• Diagonals of a square in equal in length .

therefore,

→ BC = AD

→ BC = 14 cm. (Ans.)

Learn more :-

*जर △ ABC ~ △ DEF असून AB = 12 सेमी and DE = 14 सेमी. तर △ ABC आणि △ DEF यांच्या क्षेत्रफळाचे गुणोत्तर किती?.*

1️⃣ 49/9...

brainly.in/question/37096819

*In triangle ABC, DE || AB. If CD = 3 cm, EC = 4 cm, BE = 6 cm, then DA is equal to …………….*

1️⃣ 7.5 cm

2️⃣ 3 cm

3️⃣ 4.5...

brainly.in/question/37020783

In the figure , Line PQ || Side BC AP = 6 , PB = 8 , AQ = x and QC = 12 , then write the value of x.

https://brainly.in/question/36586072

Answer 2

$\textbf{Given:}$

$\textsf{Diagonals AC and BD of a square ABCD intersect each}$

$\textsf{other at O and OA=7 cm}$

$\textbf{To find:}$

$\textsf{Length of AC and BD}$

$\textbf{Solution:}$

$\underline{\textsf{Concept used:}}$

$\textsf{1. Every square is a parallelogram}$

$\textsf{2.Diagonals of a parallelogram bisect each other}$

$\textsf{Since the diagonals AC and BD intersect at O, we have}$

$\textsf{OA=OC and OB=OD}$

$\mathsf{But\;AC=BD}$

$\implies\mathsf{OA=OB=OC=OD}$

$\mathsf{Then,}$

$\mathsf{AC=OA+OC=7+7=14\;cm}$

$\mathsf{BD=OB+OD=7+7=14\;cm}$

$\textbf{Answer:}$

$\mathsf{AC=14\;and\;BD=14\;cm}$