Question

Q.12 Factorise :
(i) 25a2
4b2 + 28bc-4ac2​

Answer 1

Answer:

Step-by-step explanation:

25a  

2

−4b  

2

−28bc−49c  

2

 

=(5a)  

2

−(2b)  

2

+28bc−(7c)  

2

 

=(5a)  

2

−{(2b)  

2

+2×2b×7c−(7c)  

2

}

     ∵[(a+b)  

2

=a  

2

+b  

2

+2ab]

=(5a)  

2

−(2b+7c)  

2

 

      ∵[a  

2

−b  

2

=(a−b)(a+b)]

={(5a)−(2b+7c)}{(5a)+(2b+7c)}

=(5a−2b−7c)(5a+2b+7c)

i hope it helps u