Question

Q-12..!!!!Find the current supplied by the cell in the circuit shown:
Please help..

Answer 1

4+1/3+1/10

=4+(10+3)/30

=4+13/30

=(120+13)/30

=133/30 ohms...

NOW, as we know,

V/R=I

=2*30/133

=60/133

=0.45 amperes...

hence the current drawn is 0.45 amperes

plz plz mark it as BRAINLIEST!

Answer 2

First solving for resistance in parallel

That will be

1/P=1/3+1/10

that will be 13/30 ohms

now 13/30 and 4ohms are in series so

R=13/30+4

=266/30

Now

V=IR

I=V/R

I=30/266*2

I=30/133 Amperes