Q-12
If a and B are the zeroes of the polynomial 6x2-x-2,
find the value of (1/a + 1/B)
Answers
Answered by
0
Answer:
-1/2
Explanation:
Given polynomial 6x^2-x-2=0
6x^2-4x+3x-2=0
2x(3x^2-2x) +1(3x^2-2) =0
(2x+1)(3x-2)=0
x= -1/2,2/3
Therefore a=-1/2 B=2/3
1/a+1/B = 1/-1/2 + 1/2/3
= -2+3/2
= -4+3/2
= -1/2
Answered by
2
Answer:
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