Question

Q 12 PHYSICS CHEMISTRY BIOLOGY MATHS On a 100 km track, a car travels the first 50 km with a uniform speed of 40 km/hr. How fast must the car travel the next 50 km so as to average 60 km/hr for the entire trip ? (Answer should be in km/hr)​

Answer 1

Answer:

Answer :

Hence , 90 km/hr fast must the car travel for the next 50 km.

Step-by-step explanation:

Total distance = 100

First distanced 1 = 50 km

Speedv1 = 30 km/h-1

The car travels 50 km with speed 30 km / hr

The time taken is

$t \: = \frac{d}{v}$

$t1 = \: \frac{50}{30}$

$t1 \: = \: 1.67 \: hr$

Let us consider, the car travels next 50 km with speed V2 km / hr.

The time taken is

$t2 \: = \: \frac{50}{v2}$

The average speed

$v \: avy \: = \: \frac{ d \: }{t}$

Here, D = total distance

T = Total time

The average speed is

$45 \: = \: \frac{100 }{ \frac{5}{3} \: + \: \frac{50}{v2} }$

V2 = 90 km / hr

Hence, 90 km/hr fast must the car travel for the next 50 km.

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Answer 2

Step-by-step explanation:

Hence, 90 km /hr fast must the car travel for the next 50 km.