Q 12 plz solve
Figure 11.38
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Step-by-step explanation:
here we are given that,
Am perpendicular to bc
since angle b =90'
in Triangle Amc
by angle sum property
cam+m+C=180
180-90+33=cam
57'=cam
in Triangle bam by angle sum
65+90+bam=180
bam=25'
angle a =bam+mac
57+25=82'
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