Q.12 :-The regression lines 5x+2y=16, and 9x+10y=48 intersect at
2,3
2,5.
Answers
Answer:
5x + 2y = 16......(I)
9x + 10y = 48......(ii)
multiply (i) by 5
25x + 10y = 80
9x + 10y = 48
by elimination method,
16x = 32
x= 2
putting value of x in equation (I),
5(2) + 2y = 16
2y = 16- 10
y = 6/2
y = 3
Hence, the line will intersect at 2,3
Given : lines 5x+2y=16 and 9x+10y = 48
To Find : Intersection point
Solution:
5x+2y=16 Eq1
9x+10y = 48 Eq2
5 * Eq1
=> 25x + 10y = 80
Subtract Eq2
=> 16x = 32
=> x = 2
Substitute x = 2 in Eq1
5x+2y=16
=> 5(2) + 2y = 16
=> 2y = 6
=> y = 3
Intersection point
x = 2 , y = 3
( 2, 3)
lines 5x+2y=16 and 9x+10y = 48 intersects at (2 , 3)
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