Question

Q.12
The work done in pushing a block of mass 10 kg from
bottom to the top of a frictionless inclined plane 5 m
long and 3 m high is- (g=9.8 m/sec)
(A) 392J (B) 294J (C) 98 J (D) 0.98 J

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Answer 1

Given :-

Mass of the block = 10 kg

Length on frictionless inclined plane = 5 m

Height from the bottom = 3 m

To Find :-

The work done in pushing a block.

Analysis :-

Here we are given with the mass and the height.

In order to find the work done substitute the given values from the questions accordingly such that work done is equal to mass into gravity into height.

Solution :-

We know that,

• m = Mass
• w = Work done
• g = Gravity
• h = Height

Using the formula,

$\underline{\boxed{\sf Potential \ energy=Mass \times Gravity \times Height}}$

Given that,

Mass (m) = 10 kg

Gravity (g) = 9.8 m/s

Height (h) = 3 m (no work done against friction)

Substituting their values,

⇒ w = mgh

⇒ w = 10 × 9.8 × 3

⇒ w = 98 × 3

⇒ w = 294 J

Therefore, the work done in pushing a block is (B) 294 J.

Answer 2

Answer:

Given :-

• A mass 10 kg from bottom to the top of a frictionless inclined plane 5 m long and 3 m high. [g = 9.8 m/s]

To Find :-

• What is the work done by pushing a block.

Formula Used :-

★ W = mgh ★

where,

• W = Work done
• m = Mass
• g = Acceleration due to gravity
• h = Height

Solution :-

Given :

• Mass (m) = 10 kg
• Acceleration due to gravity (g) = 9.8 m/s
• Height (h) = 3 m

According to the question by using the formula we get,

⇒ W = mgh

⇒ W = 10 × 9.8 × 3

⇒ W = 9.8 × 30

➠ W = 294 J

∴ The work done by pushing a block is 294 J .

Hence, the correct options is option no (B) 294 J .