Question

Q.12. The work function (WE) of some metals is listed below. Find the name of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metals given below :

Answer 1

we know , E = work function + K.E

put E = hc/lambda

then ,

as we know K.E =1/2 mv2

thus, calculate the value of v

v=c/lambda

put the value of v

6.63*10^-34 . 3*10^8/ 300*10^-7

converting 300 nm to m 300*10^-7

calculating 6.63 *10-19

v = 10*-15 and by putting the values u will get ur answer