Question

Q-12: What is the value of p(2) for the polynomial p(t)=2+t+2t2-t3​

Answer 1

Answer:

2+t+2t2-t3

put t=2 then

2+2+2×2×2-2×3

=6

Answer 2

Answer:

9

Step-by-step explanation:

P(t)=2+t+2t2-t3 then the values of p(0),p(1),p(2) are respectively

p(t)=2+t+2t2-t3

p(0)=2+0+2*0*2-0*3

=2

p(1)=2+1+2*1*2-1*3

=4

p(2)=2+2+2*2*2-2*3

=9

I hope you are satisfied

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