Math, asked by pintu6719, 11 months ago

Q.120) the logistic population growth is expressed by the equation

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Answered by anandkumar57
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The continuous version of the logistic model is described by the differential equation

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K,

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)where r is the Malthusian parameter (rate of maximum population growth) and K is the so-called carrying capacity (i.e., the maximum sustainable population). Dividing both sides by K and defining x=N/K then gives the differential equation

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)where r is the Malthusian parameter (rate of maximum population growth) and K is the so-called carrying capacity (i.e., the maximum sustainable population). Dividing both sides by K and defining x=N/K then gives the differential equation (dx)/(dt)=rx(1-x),

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)where r is the Malthusian parameter (rate of maximum population growth) and K is the so-called carrying capacity (i.e., the maximum sustainable population). Dividing both sides by K and defining x=N/K then gives the differential equation (dx)/(dt)=rx(1-x), (2)

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)where r is the Malthusian parameter (rate of maximum population growth) and K is the so-called carrying capacity (i.e., the maximum sustainable population). Dividing both sides by K and defining x=N/K then gives the differential equation (dx)/(dt)=rx(1-x), (2)which is known as the logistic equation and has solution

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)where r is the Malthusian parameter (rate of maximum population growth) and K is the so-called carrying capacity (i.e., the maximum sustainable population). Dividing both sides by K and defining x=N/K then gives the differential equation (dx)/(dt)=rx(1-x), (2)which is known as the logistic equation and has solution x(t)=1/(1+(1/(x_0)-1)e^(-rt)).

The continuous version of the logistic model is described by the differential equation (dN)/(dt)=(rN(K-N))/K, (1)where r is the Malthusian parameter (rate of maximum population growth) and K is the so-called carrying capacity (i.e., the maximum sustainable population). Dividing both sides by K and defining x=N/K then gives the differential equation (dx)/(dt)=rx(1-x), (2)which is known as the logistic equation and has solution x(t)=1/(1+(1/(x_0)-1)e^(-rt)).

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