Question

Q.13)
A bas of mass 10,ooo kg is moving with a
velocity of 60 kmph. Calculate the work
done to stop this bus.​

Answer 1

Answer:

1,388,888.889 J

Explanation:

Mass of the bus is 10,000 kg

Velocity = 60 km/h = (60 x 1000) m/hr = 60,000/3600 m/s = (50/3) m/s

Now work done = change in kinetic energy

Here, initial kinetic energy (in joule)

= (1/2).m.v²

= (1/2) x 10000 x (50/3)²

= 1,388,888.889

As the bus stops finally the final velocity is zero,

thus its final kinetic energy will be also 0 [ (1/2) x 10000 x 0 = 0 ]

@,net work done

= initial KE - Final KE

= 1,388,888.889 - 0

= 1,388,888.889 J

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