Question

Q-13 a mass 6 newton acts on a а body of mass kg for 2-0 second consuming the body to be initial at rust Find - 1- It's velocity when force stop acting 2- the distance covered 5 second after force acting​

Answer 1

Answer:

Force (F) = 6 N; Initial velocity (u) = 0;

Mass (m) = 1 kg and final velocity (v) = 30 m/s.

Therefore acceleration (a) =F/m=6/1=6m/s^2

and

final velocity (v) =u+at

30=0+6×t

30/6=t

5=t

5sec