Q.13
A solenoid of length 25 cm has inner radius of 1 cm and is made up of 250 turns of copper
wire, for a current of 3 A in it. What will be the magnitude of the magnetic field inside the
solenoid?
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0
Answer:
The magnetic field inside the solenoid:
B=μ
0
in=μ
0
i(
l
N
) where i=0.30 ,l=0.25m, N=200. This yields
B=3.0×10
−4
T
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