Q.13 Find the value of x which satisfies the relation?
Logo 3. log... (4x1)=log (x+1)+1
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log10 3+log10 (4x+1)=log10 (x+1)+1 Log10 3+log10 (4x+1)=log10 (x+1)+log10 (x+1)+log10 10 Log10 (3(4x+1))=log10 (10(x+1)) =3(4x+1)=10(x+1)=12x+3 =10x+10 =2x=7 x=7/2
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