Question

Q(13). Find two m.
secutive positive integers, sum of whose squares is 365.
Q(14.) Find two consecutive pos
of two numbers is 15, if the sum of their reciprocals is 3), find the numbers.
10
75. The sum of two numbe​

Answer 1

Answer:

$1. \\ let \: number \: be \: x \: and \: x + 1 \\ according \: to \: question... \\ {x}^{2} + ({x + 1})^{2} = 365 \\ {x}^{2} + {x}^{2} + 1 + 2x = 365 \\ {2x}^{2} + 2x - 364 = 0 \\ or \\ {x}^{2} + x - 182 = 0 \\ {x}^{2} + 14x - 13x - 182 = 0 \\ x(x + 14) - 13(x + 14) \\ we \: get \\ x = - 14 \: \: \: \: \: x = 13$