Question

Q.13. Please answer quickly

Answer 1

d = v0t + ½gt²

500 = 5 t² ( bcoz v0 = 0)...

t = 10s

now....
,

time taken for sound from pound to top of the building is,

t = d / v

t = 500 / 340

t = 25/17 s

total time = 10 + 25/17 seconds.... after the splash will hear at top of the building.....

HOPE IT HELPS....
AND HOPE MY ANSWER IS SATISFACTORY....

SO PLZ MAKE IT BRAINLIEST

Answer 2

As Given,

Height (S) = 500 m

Velocity of Sound = 340 m/s.

Acceleration due to Gravity (g) = 10 m/s^2

By using, Second Equation of Motion we can find out.

As this Can be Solved by taking two terms of time i.e.

First time = t1

Second time = t2

$= > \: s \: = ut \: + \frac{1}{2} g t_{1}^{2}$

$= > 500 = 0 + \frac{1}{2} \times 10 \times {t}_{1} ^{2}$

$= > \frac{500}{5} = \: {t}_{1} ^{2}$

$= > \: {t}_{1} ^{2} = 100 \: {s}^{2}$

$= > {t}_{1} \: \: = \sqrt{100 \: {s}^{2} }$

$= > \: t_{1} \: \: = 10 \: \: s$

Again,

For Second time.

As we know that,

=> Time = Distance/Speed

$= > t_{2} =( \dfrac{500}{340} ) \: s \:$

$= > t_{2} \: = 1.47 \: \: s \:$

Now,

Total time = t1 + t2 = ( 10 + 1.47) s = 11.47 s