Math, asked by qsaniya37, 9 months ago

Q.(13) : sinA.cotA = ?​

Answers

Answered by Sudhir1188
1

Answer:

cosA

Step-by-step explanation:

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Answered by Anonymous
15

 \huge {\purple{ \mathfrak{answer♡}}}

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 \large \sin \: A.cot \:A  \\  \\ \large sin \: A. \frac{cos \:A }{sin \: A}  \\  \\  \huge = cos \: A

 {\boxed{ \green{answer = cos \: A}}}

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