Q.13 The product of two zeros of the polynomial f(x) = 2x 3 + 6x 2 -4x + 9
is 3, then find its third zero.
Answers
Answered by
1
Answer:
Given:
Polynomial equation, f(x) = 2x³ +6x² -4x+9
Product of 2 zeroes = pq = 3
To find:
Third zero of the equation = r =?
Solution:
Condition to find zeros of polynomial, f(x) = 0.
f(x) = 2x³ +6x² -4x+9 = 0
Comparing the above equation with ax³ +bx² +cx+d = 0, we get,
a = 2, b = 6, c = -4, d = 9
Now,
pqr = -d/a
3r = -9/2
r = -9/6 = -3/2
r = -1.5
Third zero of the equation = r = -1.5
Answered by
3
f(x)= 2x
3
+ 6x
2
− 4x+ 9
Let three zeroes be α,β,γ
Product of 3 zeroes
=
a
−d
=
2
−9
Given Product of 2 zeroes
=
3
or
α.β=
3
⇒ αβγ=
2
−9
⇒ 3γ=
2
−9
⇒ γ=
2
−3
Third zero is
2
−3
thank u for asking & u can also mark me as brainlyest
Similar questions