Q. 14. 4 capacitors, each of 2 uF, are connected as shown. What will be the equivalent capacitor across the points A, B?
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Given info : four capacitors , each of 2 μF , are connected as shown in figure.
To find : the equivalent capacitor across the points A and B is ..
solution: you see, there is no any capacitor between points A and C. so we can assume these as a single point.
now , the arrangement of the capacitors is shown in figure.
step 1 : two capacitors are joined in parallel as you can see in figure.
so, C₁ = 2μF + 2μF = 4μF
step 2 : 4μF and 2μF are joined in series.
so, C = 4μF 2μF/(4μF + 2μF) = 4/3 μF
step 3 : 4/3 μF and 2μF are joined in parallel,
so, equivalent capacitance, Ceq = 4/3 + 2 = 10/3 μF
therefore the euivalent capacitor across the points A and B is 10/3 μF.
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Answer:
8 uf
Explanation:
because all of these are connected inparallel
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