Question

Q.14 A force of 300 N is applied on a mass of 25 kg, the acceleration of the mass is _______ m/s2 *​

Answer 1

Answer:

F = ma

⇒a = F/m = (300 / 25)m/s²

⇒Acceleration = 12 m/s²

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Answer 2

Given :-

• A force of 300 N is applied on a mass of 25 kg.

To find :-

• Acceleration of a body

Solution :-

• Force = 300 N

• Mass = 25 kg

As we know that

→ F = m × a

Where " F " is force, " m " is mass and " a " is acceleration.

Now

• According to the question

→ F = m × a

• Put the values

→ 300 = 25 × a

→ a = 300/25

→ a = 12 m/s²

Hence,

• Acceleration of a body is 12m/s²

More to know :-

• v = u + at (First equation of motion)

• s = ut + ½ at² (Second equation of motion)

• v² = u² + 2as (Third equation of motion)

• F = m(v - u)/t where " m " is mass