Question

Q. 14
A torque of 400 Nm acting on a body of mass 40 kg produces an angular
acceleration of 20 rad per second square Calculate moment of inertia.​

Answer 1

Answer:

Moment of Inertia = 20 Kg m^2

Radius of Gyration = 0.707 m

Explanation:

Given,

The torque = 400 Nm

The mass of the body = 40 kg

Angular acceleration = 20 rad/ s^2

Moment of Inertia = Torque/ Angular acceleration

Moment of Inertia = 400/ 20

Moment of Inertia = 20 Kg m^2

moment of Inertia = Mass(Radius of gyration)^2

20 = 40 K^2

K^2 = 1/2

K = Under root (1/2)

K = 0.707 m

Radius of gyration = 0.707 m

Explanation:

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Answer 2

Answer:

Moment of inertia of body is 20 kgm^2.

Explanation:

Given,

T = 400 Nm

a = 20 rad/s^2

By applying formula of torque

We get,

T = Ia

I = T / a

I = 400 / 20 kgm^2

I = 20 kgm^2

Here,

T is the torque of the given body.

I is the moment of inertia of the given body.

a is the angular acceleration of the given body.

Hence,

Moment of inertia of body is 20 kgm^2.