Math, asked by gangwar30, 3 months ago

Q.14 Case study-
The following distribution shows the daily pocket allowns to the children of a multi story
building:
Daily pocket money
11-13 13-15
15-17
17-19
19-21
No of children
6
13
20
7
(a) How many children get daily pocket money up to Rs 15?
10
11
12 (iv) 13
(b) Model class of the given distribution is :
19 - 21
15 - 17 (iii) 17 - 19 (iv) 11 - 13
(c) Median class of the given distribution is :
17 - 19
19 - 21
(111 11 - 13 (iv) 13 - 15
(d) Lower limit of the modal class is:
19
21
11
13
le) Product of lower limit of median class and upper limit of model class is :
(i) 260
357
402 (iv)
368
(iv)
Ate​

Answers

Answered by jasoriasarika
1

Answer:

Let the missing frequency be x.

Class interval Frequency xi fixi 11-13 7 12 84 13-15 6 14 84 15-17 916 144 17-19 13 18 234 19-21 x 20 20x 21-23 5 22 110 23-25 4 24 96  Σfi=44+x  Σfixi=752+20x average pocket allowance xˉ=ΣfiΣfixi=18⇒(given)

∴44+x752+20x=18

⇒752+20x=18(44+x)

⇒752+20x=792+18x

⇒2x=40

⇒x=20

Hence, the missing frequency is 20.

Answered by dasabhijeet
0

Step-by-step explanation:

हाउ मेनी चिल्ड्रन गेट दिल्ली पॉकेट मनी ऑफ ₹2 गिफ्ट

Similar questions