Math, asked by stwowthakur, 8 months ago

Q 14.

If y = 3 e 2x + 2e3x, then
- 5+6y
dx
is
2
dx
OO
Ο Ο
O 2
2​

Answers

Answered by Anonymous
0

Answer:

BRO WHAT IS YR QUESTION

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Answered by Anonymous
0

Answer:

y = 3e {}^{2x}  + 2e {}^{3x}

 \frac{dy}{dx}  = 6e {}^{2x}  + 6e {}^{3x}

 \frac{d {}^{2} y}{dx {}^{2} }  = 12e {}^{2x}  + 18e {}^{3x}

Condition:

 \frac{d {}^{2} y}{dx {}^{2} } - 5 \frac{dx}{dy}   + 6y = 0

12e {}^{2x}  + 18e {}^{3x}  - 5(6e {}^{2x}  + 6e {}^{3x} ) + 6(3e {}^{2x}  + 2e {}^{3x} )

12e { }^{2x}  + 18e {}^{3x}  - 30e {}^{2x}  - 30e {}^{3x}  + 18e {}^{2x}  + 12e {}^{3x}

30e {}^{2x}  + 30e {}^{3x}  - 30e {}^{2x}  - 30e {}^{3x}  = 0

Hence 0 is the answer.

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