Question

Q.14 Find a relation between x and y so that the point (x,y) is equidistant from the points (-4,-4) and (-2,4).
A. 4x-3y-3=0
B. x+4y+3=0
C. 4x+y+3=0
D. x-4y+3=0​

Answer 1

Answer:

option(b) x+4y+3=0

Step-by-step explanation:

let the points be a1(-2,4) a2(x,y) a3(-4,-4)

given a2 is equidistant from a1 and a3

i.e

(x+2)²+(y-4)²=(-4-x)²+(-4-y)² by distant formula

x²+4+4x+y²+16-8y=16+x²+8x+16+y²+8y

4+4x+16-8y=16+8x+16+8y

4+4x-8y=8x+16+8y

4x-8x-8y-8y+4-16=0

-4x-16y-12=0

4x+16y+12=0

x+4y+3=0