Question

Q: 14. it is known that
a box of
боо bulk,
contains 12 defective bulles One bulb is
taken out randomly from this box. what
is the
Probability that
defective.
nom-​

Answer 1

Step-by-step explanation:

The probability that one bulb taken out random is non-defective is \dfrac{49}{50}

50

49

.

Step-by-step explanation:

Given as :

The number of bulb in the box = 600

The number of defective bulb in box = 12

Let The probability that one bulb taken out random is non-defective = p(E)

According to question

As out of 600 bulbs, 12 bulbs are defective

So, The number of non-defective bulb = 600 - 12 = 588

Now, out of 600 bulbs, 1 bulb is chosen in {C_{1}}^{600}C

1

600

And favourable case of chosen non-defective = {C_{1}}^{588}C

1

588

So, probability = \frac{{C_{1}}^{588}}{{C_{1}}^{600}}

C

1

600

C

1

588

Or, p(E) = \dfrac{588}{600}

600

588

Or, p(E) = \dfrac{49}{50}

50

49

Hence, The probability that one bulb taken out random is non-defective is \dfrac{49}{50}

50

49