Question

Q.14] The length of a hypotenuse of an isosceles right angled triangle is 50 cm. Find its area
Please Answer Soon​

Answer 1

let abc be the sides of the∆

we know.

a=b (sides of isosceles triangle)

L b= 90° ( given)

thus, L bca and L bac= 45° each

Now, sin45°= a/c

1/√2= a/50 cm

a= 50×1/√2 cm= 50/√2 cm= 25√2 cm

Area of a ∆ = 1/2( b×h)

= 1/2(25√2 cm×25√2 cm)

= 625×2cm²/2

= 625cm²