Question

Q.14 The two zeroes of the polynomial x2 – 3 are
​

Answer 1

Answer:

Given polynomial is x  

2

−3  

Here, a=1,b=0  and c=−3

x  

2

−3=(x−  

3

​

)(x−  

3

​

)

So, the value of x  

2

−3 is zero when x=  

3

​

 or x=−  

3

​

 

Threrfore , thr zeroes of x  

2

−3  are  

3

​

  and −  

3

​

.

Now, sum of zeroes =  

3

​

−  

3

​

=0=  

1

0

​

=  

a

−b

​

 

product  of zeroes =(  

3

​

)(−  

3

​

)=−3=  

1

−3

​

=  

a

c

​

 

Hence verified.

Step-by-step explanation:

Answer 2

Answer:

To find the zeroes do like this:

x^2-3=0

x^2-(√3)^2=0 [ this is in a^2 - b^2 form]

(x+√3)(x-√3)=0

x+√3=0 , x= -√3

x-√3=0, x=+√3

Ans is -√3 and √3