Physics, asked by kaurgurnaman9, 19 days ago

Q.14. Two billiard balls A and B of mass 50 g each and moving in opposite directions with speed of 5 m/s each, collide and rebound with the same speed. If the collision lasts for 10-'s, which of the following statements are true (a) the change in momentum of each ball is 0.25 kg m/s and the force on each ball is 250N (b) the impulse imparted to each ball is 0.25 kg m/s and the force on each ball is 25 x 10-5N.​

Answers

Answered by ShariqueJ
1

Answer:

Two billiard balls A and B, each of mass 50 g and moving in opposite directions with speed of 5 ms

−1

each, collide and rebound with the same speed. The impulse imparted to each ball is:

Medium

Solution

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Correct option is

B

0.5Kgms

−1

Mass of each ball,m=50g=0.05 kg

Initial velocity, v

1

=5 m/s

Initial Momentum , P

1

=mv

1

=0.05×5=0.25kg m/s

After collision, the direction of velocity of each ball is reversed on rebounding.

Final momentum, P

2

=m×(−v

1

)=0.05×(−5)=−0.25kg m/s

Impulse imparted on each ball = Change in momentum of each ball after collision

J=P

1

−P

2

=0.25−(−0.25)=0.5kg m/s

∴ Impulse imparted due to one ball after collision on another is equal to 0.5kg m/s

plss mark brainliest

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