Q.142 A ball is released from rest from a tower of height 3h. The ratio of the
intervals of time to cover three equal heights h is t1: t2: 13.
a 1:(12-1):(13–2)
b 1: 12:13
c 13:2:1
d 1: (12-1) : (13– 2)
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A particle is released from rest from a tower of height 3h. The ratio of the intervals of time to cover three equal heights h is:
Option D
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ANSWER
For A to B−
h=(a)(t
1
)+
2
1
gt
1
2
[2
nd
equation of motion.]
t
1
=
g
2h
..................(1)
From A to C−
2h=(0)(t
2
)+
2
1
gt
2
2
t
2
=
g
4h
..................(2)
Similarly, t
3
=
g
6h
........(3
)
Times taken from A to B=t
1
=
g
2h
Times taken from B to C=t
2
−t
1
=
g
4h
−
g
2h
=
g
2h
(
2
−1)
Time taken from C to D=t
3
−t
2
=
g
6h
−
g
4h
=
g
2h
(
3
−
2
)
∴ Ration =1:(
2
−1):(
3
−
2
)
Option- D
Hope this helps you☺
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