Question

Q.14a)Prove that angles opposite to equal sides of an isosceles triangle are
equal.​

Answer 1

Step-by-step explanation:

Given: In the isosceles ∆XYZ, XY = XZ.

To prove ∠XYZ = ∠XZY.

Construction: Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M.

Proof:

Statement

1. In ∆XYM and ∆XZM,

(i) XY = XZ

(ii) XM = XM

(iii) ∠YXM = ∠ZXM

2. ∆XYM ≅ ∆XZM

3. ∠XYZ = ∠XZY. (Proved)

Reason

1.

(i) Given.

(ii) Common side.

(iii) XM bisects ∠YXZ.

2. By SAS criterion.

3. CPCTC.

Answer 2

Answer:

In triangle ABC

sum of angles of triangle is 180 degree

let angle B ,angle C = x

A=90 degree.

now, A+B+C = 180

A+ x+x =180

A+2x= 180

2x= 180-90

2x=90

x=45 degree.

so, B is 45 degree= C is 45 degree.

hence,angles opposite to equal sides an isosceles triangle are

equal.