Question

Q.15. A bullet is fired with a velocity of 150m/s. It penetrates a wood by 5 cm and stops. Find the
retardation of the bullet and the time interval in which the bullet stops.​

Answer 1

Answer:

3000m/s and 0.2sec

Step-by-step explanation:

After taking out the retardation use the formula v=u+at

Answer 2

Answer:

Time taken by bullet to stop is 2/3s

Retardation is 255m/s²

Step-by-step explanation:

Given-

initial velocity (u)= 150m/s

final velocity(v)= 0m/s

Distance (S)= 5cm = 0.05m

Let time taken by bullet to stop be t,

Therefore, Since velocity (u) = S/t

=⟩ t = S/u = 0.05/150 = 2/3s

retardation = avg.velocity/time

= 150/(2/3) = (150×3)/2

= 225 m/s²

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