Question

Q 15). A die is thrown, the
probability of getting a multiple
of four on the upper face is​

Answer 1

Answer:

Step-by-step explanation:

Total no. of outcomes; n(s) = 6 [1, 2, 3, 4, 5, 6]

P(getting a multiple of 3) = n(e)/ n(s)

4/6 = 2/3

Answer 2

Given :

• A Die is thrown.

To Find :

• Probability of getting a multiple of 4.

Solution :

$\longmapsto\tt{Total\:Outcomes=6\:(1,2,3,4,5,6)}$

$\longmapsto\tt{Favourable\:Outcomes=1\:(4)}$

$\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}$

$\longmapsto\tt\bold{\dfrac{1}{6}}$

So , The Probability of getting a multiple of 4 is 1/6...

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Probability :

It is defined as chances of happening or occuring of an event.

• Probabilty of an event always lies between 0 and 1.
• Probability of an event can never be negative.

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