Q.15
A ship of mass 3 × 107 kg initially of rest is pulled by a force of 5 × 104 N through a distance of 3 m. If water resistance is neglected, speed of ship is
Choose answer:
1.5 m/s
60 m/s
0.1 m/s
5 m/s
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I will explain it so that you can understand easily..
You know that Force = Mass × Acceleration
So Firstly find that and Then You have to Apply Newton's Third Law...
So Stepwise solved this answer As Follows :
F=ma. (Force = Mass×Acceleration)
5*104 = (3*107) a
a = (5/3)*10-3
This is the acceleration.
Now, By newton’s third law of motion,
v2 – u2 =2as
v2 – 02 = (2)*(5/3)*(10-3)(3)
v2 = 10-2
v = 0.1 m/s. Ans.
You know that Force = Mass × Acceleration
So Firstly find that and Then You have to Apply Newton's Third Law...
So Stepwise solved this answer As Follows :
F=ma. (Force = Mass×Acceleration)
5*104 = (3*107) a
a = (5/3)*10-3
This is the acceleration.
Now, By newton’s third law of motion,
v2 – u2 =2as
v2 – 02 = (2)*(5/3)*(10-3)(3)
v2 = 10-2
v = 0.1 m/s. Ans.
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