Question

Q.15 An object undergoes simple harmonic motion. Its amplitude is xo. The speed
of the object is v when its displacement Is xo/3. What is the speed when its
displacement is so?
A. v/3
C. 3/2 v
B. 2 v
D.O

Answer 1

D. 0 is the speed at which the object undergoes simple harmonic motion.

Explanation:

• Amplitude is $\[{{x}_{0}}\]$

• The speed of the object is, v

• The first displacement of the object, $\[{x}_{1}=\frac{{{x}_{0}}}{3}\]$

• The second displacement of the object, $\[{x}_{2}=\frac{{{x}_{0}}}{3}\]$

• The formula for velocity is ,$\[V={{x}_{0}}\omega \]$

• Therefore, at the mean position, the velocity of the particle performing simple harmonic motion is maximum V.

• Here $\[{{V}_{0}}={{V}_{\max }}\]$ is equal.

• Therefore Speed at, $\[{{x}_{2}}={{x}_{0}}\]$

• Hence speed is zero.