CBSE BOARD X, asked by rairachna03Rachna, 1 year ago

Q 15 first part answer plz not explain

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Answered by 22Khushi
1
In a parallelogram the diagonals bisect each other

Midpoint of AC = midpoint of BD

Midpoint formulae (x1+x2)/2 ; (y1+y2)/2

(-2+4)/2 ; (1+b)/2 = (a+1)/2 ; (0+2)/2

2/2 ; (1+b)/2 = (a+1)/2 ; 2/2

=> 1=(a+1)/2

a+1 = 2

a=1

=> (1+b)/2 = 1

1+b=2

b= 1

a=1 and b=1


Using distance formula we came find out the length of the sides of parallelogram

Distance formula √[(x2-x1)²+(y2-y1)²]

AB = √[(1+2)²+(0-1)²]

= √(9+1)

=√10u

BC = √[(4-1)²+(1-0)²]

= √(3²+1²)

= √10u

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22Khushi: mmm.....half marks
22Khushi: i guess
rairachna03Rachna: Agar Maine surf a and b ki value Nike has to kite milege
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