Q 15 first part answer plz not explain
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In a parallelogram the diagonals bisect each other
Midpoint of AC = midpoint of BD
Midpoint formulae (x1+x2)/2 ; (y1+y2)/2
(-2+4)/2 ; (1+b)/2 = (a+1)/2 ; (0+2)/2
2/2 ; (1+b)/2 = (a+1)/2 ; 2/2
=> 1=(a+1)/2
a+1 = 2
a=1
=> (1+b)/2 = 1
1+b=2
b= 1
a=1 and b=1
Using distance formula we came find out the length of the sides of parallelogram
Distance formula √[(x2-x1)²+(y2-y1)²]
AB = √[(1+2)²+(0-1)²]
= √(9+1)
=√10u
BC = √[(4-1)²+(1-0)²]
= √(3²+1²)
= √10u
Midpoint of AC = midpoint of BD
Midpoint formulae (x1+x2)/2 ; (y1+y2)/2
(-2+4)/2 ; (1+b)/2 = (a+1)/2 ; (0+2)/2
2/2 ; (1+b)/2 = (a+1)/2 ; 2/2
=> 1=(a+1)/2
a+1 = 2
a=1
=> (1+b)/2 = 1
1+b=2
b= 1
a=1 and b=1
Using distance formula we came find out the length of the sides of parallelogram
Distance formula √[(x2-x1)²+(y2-y1)²]
AB = √[(1+2)²+(0-1)²]
= √(9+1)
=√10u
BC = √[(4-1)²+(1-0)²]
= √(3²+1²)
= √10u
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