Question

Q 15) In A ABC, AP 1 BC, BQL AC B-2
P-C, A-Q-C then prove that, A CPA ~
ACQB. If AP = 7, BQ = 8, BC = 12 then
find AC.*
ob
BT
c
P
AC = 9.5
O AC = 10.5
O
AC = 8.5
AC= 12.5​

Answer 1

Step-by-step explanation:

In ΔCPA and ΔCQB

AP⊥BC........GIVEN

BQ⊥AC........GIVEN

∠CPA=90°............1

∠CQB=90°............2

∠CPA≅∠CQB.........from 1 and 2

∴ΔCPA~ΔCQB

In ΔABC

AP=7

BQ=8

BC=12

AC=?

∴AP/BQ=AC/BC

∴7/8=AC/12

∴AC= 12 x 7/8

∴AC=10.5