Question

Q.15 of 24
A coin is tossed 1000 times .Head
comes 440 times.what is the
probability of getting a tail
(1 marks)​

Answer 1

Answer:

first,

first, no. of times we obtained tails=1000-440 = 560

first, no. of times we obtained tails=1000-440 = 560probability of getting tails =560/1000= 28/50

first, no. of times we obtained tails=1000-440 = 560probability of getting tails =560/1000= 28/50pls vote and follow.....

Answer 2

Answer:

The probability of head is 0.455 and the probability of tail is 0.545.

Given:

Total outcomes = 1000

Frequency of head = 455

Frequency of tails = 545

i) The probability of heads =\frac{\text {Number of time head drawn}}{\text {Total number of times tossed}}=

Total number of times tossed

Number of time head drawn

\begin{gathered}\begin{aligned} &=\frac{455}{1000} \\ &=0.455 \end{aligned}\end{gathered}

=

1000

455

=0.455

ii) Probability of tail =\frac{\text { Number of time tail drawn }}{\text { Total number of times tossed }}=

Total number of times tossed

Number of time tail drawn

\begin{gathered}\begin{array}{l}{=\frac{545}{1000}} \\ {=0.545}\end{array}\end{gathered}

=

1000

545

=0.545