Q.15 pls solve . Right answer will be marked as Brainliest.
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When u substitute,
y^2 - y - 6=0
y^2 - 3y + 2y -6 =0
y(y-3)+2(y-3)=0
therefore,
y=3 or y= -2
y^2 - y - 6=0
y^2 - 3y + 2y -6 =0
y(y-3)+2(y-3)=0
therefore,
y=3 or y= -2
vaibhavc1:
oh ha sorry
y ki value ayi hai ab ((a+b)^2 )x^2 =y kr k
(a+b)x=y
hmm
substitute
are u in grade 9 ICSE?
10 icse
oh, same here
nyc
Thx a lot for marking as brainliest answer! :)
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