Question

Q.15 - The sum of the three number is 68.If the ratio of the first to
second is 3:2 and that of the second to the third is 5:3 , then the
second number is​

Answer 1

Answer:

sorry

Step-by-step explanation:

i don't know the answer hope u get it

Answer 2

Lets assume those three numbers to be a, b, c.
a:b = 3x : 2x,. ........ (Step1)
b:c = 5y : 3y. ........ (Step2)
a(q)+b(q)+c(q) = 68 ................ (Step3)
where 'q' is an integer to be found.
From "b" of Step1 & Step2, we get,
b = 2x = 5y
To get a single value for "b", let's put
x=5 and y=2. ......... (Step4)
therefore, b = 2(5) = 5(2) = 10 ..... (Step5)
Applying Step4 in Step1 & Step2, we get,
a:b = 3(5) : 2(5) = 15 : 10
b:c = 5(2) : 3(2) = 10 : 6
therefore, a:b:c = 15 : 10 : 6 .........Step6
Applying Step6 in Step3, we get,
15(q) + 10(q) + 6(q) = 68. ......Step7
let's put q = 2,
15(2) + 10(2) + 6(2) = 30 + 20 + 12 = 62.
.....................................................(Step8)
I'm sorry, the above question is wrong as 68 is not a possible sum of
a(q)+b(q)+c(q) with the given ratios of a:b:c