Q.16 A body of mass 0.10 kg is being revolved in a circular path of diameter 1 point
1.0 m on a friction less horizontal plane by means of a string. It performs 10
revolutions in 31.4 seconds. The centripetal force acting on the body is -
O 0.2N
ON
O 20 N
O 0.3N
Answers
Answered by
0
Explanation:
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Answered by
3
Explanation:
Centripetal force acting on a body having angular velocity ω and radius of circle 'r' is
ω=
t
θ
=
31.4
10×2π
=2 rad/s
F=mv
2
/r=mrω
2
F=0.1×0.5×2
2
=0.2 N
therefore correct answer is option a
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