Question

Q. 16. A compound is formed by two elements M and N.
The element N forms ccp and M atoms occupy 1/3 of
tetrahedral voids. What is the formula of the compound?

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Answer 1

Answer :

• Formula of the compound is $\rm{M_2N_3.}$

Step-by-step explanation :

Given that,

• Element N forms ccp arrangement.

• Atoms of element M occupy 1/3 of tetrahedral voids.

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Given that N forms ccp arrangement. Hence, it will have 4 atoms in a unit cell.

∴ Number of N atoms in unit cell = 4.

Also, for each atom, there are two tetrahedral voids so that there are 8 tetrahedral voids per unit cell.

Then, according to the given data,

No. of M atoms = $\rm{\dfrac{1}{3}\times{}8=\dfrac{8}{3}}$

∴ Formula of the compound :-

$\implies\rm{M_{8/3}N_4}$

$\implies\bold{M_2N_3.}$

Answer 2

Answer:

It is given that the atoms of element M occupy 1/3rd of tetrahedral voids. Hence , the formula of the compound is M2N3.