Q.16 Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32 Cm
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Step-by-step explanation:
sides are a and a = 8 cm and 11 cm
perimeter of the triangle = a + a + a
32 = 8 + 11 + a
32 - 8 - 11 = a
13 = a
Now by heron's formula = s√(s-a) (s-b) ( s-c)
where a = 8
b = 11
c = 13
and s = semi perimeter
= 16
so, plug these all values and get the answer buddy !
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