Question

Q.16 For any positive integer , prove that

3 − is divisible by 6​

Answer 1

Answer:

Out of three (n – 1), n, (n + 1) one must be even, so a is divisible by 2. 2. (n – 1) , n, (n + 1) are consecutive integers thus as proved a must be divisible by 3. Thus, n³ – n is divisible by 6 for any positive integer n.

hope it is helpful.

Answer 2

Answer:

We know that 3 is not divisible by 6 so what we do is :

3.0 ÷ 6 so this will give us 5 which will be divisible by 6.